Message ID | 305feb971ae11e192f35f25d66bb7b2e28e06c39.1449755818.git.geliangtang@163.com |
---|---|
State | Awaiting Upstream |
Delegated to: | Pablo Neira |
Headers | show |
On 12/10/2015 07:17 AM, Geliang Tang wrote: > We already have list_is_last(), it makes sense to also add > list_is_first() for consistency. This list utility function > to check for first element in a list. Honestly, I think we already have way too many of these kind of helpers. IMHO they don't really help, they hurt readability. You should know how the list works anyway, and if you do, then it's a no-brainer what's first and last. If you don't, then you are bound to screw up in other ways. Just my 2 cents.
On Thu, Dec 10, 2015 at 08:10:34AM -0700, Jens Axboe wrote: > On 12/10/2015 07:17 AM, Geliang Tang wrote: > >We already have list_is_last(), it makes sense to also add > >list_is_first() for consistency. This list utility function > >to check for first element in a list. > > Honestly, I think we already have way too many of these kind of helpers. > IMHO they don't really help, they hurt readability. You should know how the > list works anyway, and if you do, then it's a no-brainer what's first and > last. If you don't, then you are bound to screw up in other ways. > > Just my 2 cents. Personally I would disagree. Something like: if (list_is_first(&rq->queuelist, &nd->queue)) is much more readable to me than: if (rq->queuelist.prev == &nd->queue) The first one takes no effort for me -- it's almost English. While the second one takes me a few seconds (and some precious brain cycles) to decipher. Maybe whether it's readable depends on how many years you've been looking at the pattern. But IMHO we shouldn't make "having x # of years staring at kernel code" a prerequisite for being able to read kernel code.
On 12/10/2015 08:23 AM, Josh Poimboeuf wrote: > On Thu, Dec 10, 2015 at 08:10:34AM -0700, Jens Axboe wrote: >> On 12/10/2015 07:17 AM, Geliang Tang wrote: >>> We already have list_is_last(), it makes sense to also add >>> list_is_first() for consistency. This list utility function >>> to check for first element in a list. >> >> Honestly, I think we already have way too many of these kind of helpers. >> IMHO they don't really help, they hurt readability. You should know how the >> list works anyway, and if you do, then it's a no-brainer what's first and >> last. If you don't, then you are bound to screw up in other ways. >> >> Just my 2 cents. > > Personally I would disagree. Something like: > > if (list_is_first(&rq->queuelist, &nd->queue)) > > is much more readable to me than: > > if (rq->queuelist.prev == &nd->queue) Both the function and your example are backwards, and hence a lot harder to comprehend than they should be. It'd be much clearer as: if (nd->queue.next == &rq->queuelist) which is a lot easier to read. Nobody should open-code a 'is this the first entry in the list' by asking 'is the previous link to my node the head', asking 'is the next entry in the list X' makes a lot more sense. I'm assuming this happened because the list_is_last was just copied and modified, instead of thinking about this for a second. > The first one takes no effort for me -- it's almost English. While the > second one takes me a few seconds (and some precious brain cycles) to > decipher. > > Maybe whether it's readable depends on how many years you've been > looking at the pattern. But IMHO we shouldn't make "having x # of years > staring at kernel code" a prerequisite for being able to read kernel > code. It's a balance, as we also should not make APIs out of everything. As I said, purely my opinion, but I think the is_last/is_first have jumped the shark.
On Thu, Dec 10, 2015 at 09:23:57AM -0600, Josh Poimboeuf wrote: > Personally I would disagree. Something like: > > if (list_is_first(&rq->queuelist, &nd->queue)) > > is much more readable to me than: > > if (rq->queuelist.prev == &nd->queue) > > The first one takes no effort for me -- it's almost English. While the > second one takes me a few seconds (and some precious brain cycles) to > decipher. > > Maybe whether it's readable depends on how many years you've been > looking at the pattern. But IMHO we shouldn't make "having x # of years > staring at kernel code" a prerequisite for being able to read kernel > code. I think understanding the list.h semantics is a requirement for writing (or reading) non-trivial kernel code. -- To unsubscribe from this list: send the line "unsubscribe netfilter-devel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html
On Thu, 10 Dec 2015, Jens Axboe wrote: > It's a balance, as we also should not make APIs out of everything. As I said, > purely my opinion, but I think the is_last/is_first have jumped the shark. I don't have a strong opinion either way. What I think we should do though, is to either have both (i.e accept this patchset) or have neither of them (i.e. drop list_is_last()). Otherwise people are likely to be confused by such an asymetric API and will keep posting patches for it over and over again.
diff --git a/include/linux/list.h b/include/linux/list.h index 5356f4d..2c43ef4 100644 --- a/include/linux/list.h +++ b/include/linux/list.h @@ -170,6 +170,17 @@ static inline void list_move_tail(struct list_head *list, } /** + * list_is_first - tests whether @list is the first entry in list @head + * @list: the entry to test + * @head: the head of the list + */ +static inline int list_is_first(const struct list_head *list, + const struct list_head *head) +{ + return list->prev == head; +} + +/** * list_is_last - tests whether @list is the last entry in list @head * @list: the entry to test * @head: the head of the list
We already have list_is_last(), it makes sense to also add list_is_first() for consistency. This list utility function to check for first element in a list. Signed-off-by: Geliang Tang <geliangtang@163.com> --- include/linux/list.h | 11 +++++++++++ 1 file changed, 11 insertions(+)