diff mbox

[net-next,2/2] r8152: adjust rtl_start_rx

Message ID 0835B3720019904CB8F7AA43166CEEB2ECE429@RTITMBSV03.realtek.com.tw
State RFC, archived
Delegated to: David Miller
Headers show

Commit Message

Hayes Wang Nov. 12, 2014, 5:07 a.m. UTC
David Miller [mailto:davem@davemloft.net] 
> Sent: Wednesday, November 12, 2014 10:51 AM
[...]
> Ok, but if we are looping here in rtl_start_rx() and r8152_submit_rx()
> fails due to a memory allocation failure, there is nothing which is
> going to make such a memory allocation succeed in the next iteration
> of the loop.
> 
> Unless you can prove that often it can succeed after an initial
> failure, this is just wasted work and in fact making it take longer
> for the system to reclaim memory when under pressure because these
> extra iterations are completely wasted cpu work.

How about that when a error occurs, add the remaining rx
to the list without submission? Then, the remianing rx
could be re-submitted later, and the rtl_start_rx() could
be completed as soon as possible.

 
Best Regards,
Hayes
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Comments

David Miller Nov. 12, 2014, 5:13 a.m. UTC | #1
From: Hayes Wang <hayeswang@realtek.com>
Date: Wed, 12 Nov 2014 05:07:40 +0000

> How about that when a error occurs, add the remaining rx
> to the list without submission? Then, the remianing rx
> could be re-submitted later, and the rtl_start_rx() could
> be completed as soon as possible.

I really want to know why you are spending so much effort on this.

Is there a real situation that happened very often, which you
diagnosed in detail, and therefore you want to address?
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Hayes Wang Nov. 12, 2014, 5:23 a.m. UTC | #2
David Miller [mailto:davem@davemloft.net] 
> Sent: Wednesday, November 12, 2014 1:13 PM
[...]
> I really want to know why you are spending so much effort on this.
> 
> Is there a real situation that happened very often, which you
> diagnosed in detail, and therefore you want to address?

No. I just consider the possible situation and want to
make the driver better. If you think this is unnecessary,
I would remove it.
 
Best Regards,
Hayes
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David Miller Nov. 12, 2014, 5:43 a.m. UTC | #3
From: Hayes Wang <hayeswang@realtek.com>
Date: Wed, 12 Nov 2014 05:23:03 +0000

> David Miller [mailto:davem@davemloft.net] 
>> Sent: Wednesday, November 12, 2014 1:13 PM
> [...]
>> I really want to know why you are spending so much effort on this.
>> 
>> Is there a real situation that happened very often, which you
>> diagnosed in detail, and therefore you want to address?
> 
> No. I just consider the possible situation and want to
> make the driver better. If you think this is unnecessary,
> I would remove it.

What do other USB network drivers do in similar situations?
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Hayes Wang Nov. 12, 2014, 6:29 a.m. UTC | #4
David Miller [mailto:davem@davemloft.net] 
> Sent: Wednesday, November 12, 2014 1:44 PM
[...]
> What do other USB network drivers do in similar situations?

According to the usbnet.c, it would make sure to submit the
number of min(10, RX_QLEN(dev)) rx buffers. If there are
not enough rx buffers, it schedule a tasklet for next try.

The brief flow is as following.
1. Call open().
   - schedule a tasklet.
2. Tasklet is called.
   if (dev->rxq.qlen < RX_QLEN(dev)) {
	   - submit rx buffers util the number of
	     min(10, RX_QLEN(dev)). If the error
	     occurs, break the loop.
	   - If the dev->rxq.qlen < RX_QLEN(dev),
	     schedule the tasklet.
   }

Best Regards,
Hayes
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David Miller Nov. 12, 2014, 7:49 p.m. UTC | #5
From: Hayes Wang <hayeswang@realtek.com>
Date: Wed, 12 Nov 2014 06:29:46 +0000

> David Miller [mailto:davem@davemloft.net] 
>> Sent: Wednesday, November 12, 2014 1:44 PM
> [...]
>> What do other USB network drivers do in similar situations?
> 
> According to the usbnet.c, it would make sure to submit the
> number of min(10, RX_QLEN(dev)) rx buffers. If there are
> not enough rx buffers, it schedule a tasklet for next try.
> 
> The brief flow is as following.
> 1. Call open().
>    - schedule a tasklet.
> 2. Tasklet is called.
>    if (dev->rxq.qlen < RX_QLEN(dev)) {
> 	   - submit rx buffers util the number of
> 	     min(10, RX_QLEN(dev)). If the error
> 	     occurs, break the loop.
> 	   - If the dev->rxq.qlen < RX_QLEN(dev),
> 	     schedule the tasklet.
>    }

That sounds like a better recovery model, why don't you mimick it?
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Hayes Wang Nov. 13, 2014, 2:31 a.m. UTC | #6
David Miller [mailto:davem@davemloft.net] 
> Sent: Thursday, November 13, 2014 3:50 AM
[...]
> > According to the usbnet.c, it would make sure to submit the
> > number of min(10, RX_QLEN(dev)) rx buffers. If there are
> > not enough rx buffers, it schedule a tasklet for next try.
> > 
> > The brief flow is as following.
> > 1. Call open().
> >    - schedule a tasklet.
> > 2. Tasklet is called.
> >    if (dev->rxq.qlen < RX_QLEN(dev)) {
> > 	   - submit rx buffers util the number of
> > 	     min(10, RX_QLEN(dev)). If the error
> > 	     occurs, break the loop.
> > 	   - If the dev->rxq.qlen < RX_QLEN(dev),
> > 	     schedule the tasklet.
> >    }
> 
> That sounds like a better recovery model, why don't you mimick it?

My last method which I mentioned yesterday is similar to
this one. The difference is that I would re-use the rx
buffers, so I have to add them to the list for re-submitting,
not alwayes allocate new one.

Although one rx buffer could contain many packets, I don't
think the whole size of the rx buffer is alwayes used.
Therefore, I re-use the rx buffers to avoid allocating
the 16K bytes rx buffer alwayes. This also makes sure that
I always have the buffers to submit without allocating new
one.

If you could accept this, I would modify this patch by
this way.
 
Best Regards,
Hayes
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David Miller Nov. 13, 2014, 3:31 a.m. UTC | #7
From: Hayes Wang <hayeswang@realtek.com>
Date: Thu, 13 Nov 2014 02:31:14 +0000

> My last method which I mentioned yesterday is similar to
> this one. The difference is that I would re-use the rx
> buffers, so I have to add them to the list for re-submitting,
> not alwayes allocate new one.
> 
> Although one rx buffer could contain many packets, I don't
> think the whole size of the rx buffer is alwayes used.
> Therefore, I re-use the rx buffers to avoid allocating
> the 16K bytes rx buffer alwayes. This also makes sure that
> I always have the buffers to submit without allocating new
> one.
> 
> If you could accept this, I would modify this patch by
> this way.

I'll reread your original patch and think some more about this.

Thanks.
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David Miller Nov. 13, 2014, 9:22 p.m. UTC | #8
From: David Miller <davem@davemloft.net>
Date: Wed, 12 Nov 2014 22:31:46 -0500 (EST)

> From: Hayes Wang <hayeswang@realtek.com>
> Date: Thu, 13 Nov 2014 02:31:14 +0000
> 
>> My last method which I mentioned yesterday is similar to
>> this one. The difference is that I would re-use the rx
>> buffers, so I have to add them to the list for re-submitting,
>> not alwayes allocate new one.
>> 
>> Although one rx buffer could contain many packets, I don't
>> think the whole size of the rx buffer is alwayes used.
>> Therefore, I re-use the rx buffers to avoid allocating
>> the 16K bytes rx buffer alwayes. This also makes sure that
>> I always have the buffers to submit without allocating new
>> one.
>> 
>> If you could accept this, I would modify this patch by
>> this way.
> 
> I'll reread your original patch and think some more about this.

What if even the first r8152_submit_rx() fails?  What ever will cause
any of these retries to trigger at all?

Second, why does your patch increment 'i' with 'i++;' in the error
break path?  You should mark the first failed entry as unallocated
with actual_length == 0 and place it on the rx_done queue.
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Hayes Wang Nov. 14, 2014, 5:14 a.m. UTC | #9
David Miller [mailto:davem@davemloft.net] 
> Sent: Friday, November 14, 2014 5:23 AM
[...]
> What if even the first r8152_submit_rx() fails?  What ever will cause
> any of these retries to trigger at all?

According to the patch #1 "adjust r8152_submit_rx", the
r8152_submit_rx() would add the rx to the list and schedule
the tasklet, when the error occurs. Each time the tasklet is
called, the rx_bottom() would deal with all the rx in the
list. If the actual_length isn't vaild, the rx buffer would be
submitted directly. By this way, the retries would be done.
That is, the retries would be triggered when the tasklet
is called. Therefore, any tx, rx, and tasklet scheduling
would result in the retries.

> Second, why does your patch increment 'i' with 'i++;' in the error
> break path?  You should mark the first failed entry as unallocated
> with actual_length == 0 and place it on the rx_done queue.

Because the r8152_submit_rx() would add the failed rx to
the list, I only have to deal with the remaining ones. That
is why I increase the "i", otherwise the failed one would
be added twice.

I remember the usb_submit_urb() would set actual_length
to 0, so I skip the step. I would check it again.
 
Best Regards,
Hayes
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diff mbox

Patch

diff --git a/drivers/net/usb/r8152.c b/drivers/net/usb/r8152.c
index 0a30fd3..3273e3d 100644
--- a/drivers/net/usb/r8152.c
+++ b/drivers/net/usb/r8152.c
@@ -1991,14 +1991,35 @@  static void rxdy_gated_en(struct r8152 *tp, bool enable)
 
 static int rtl_start_rx(struct r8152 *tp)
 {
+	struct list_head rx_queue;
 	int i, ret = 0;
 
 	INIT_LIST_HEAD(&tp->rx_done);
 	for (i = 0; i < RTL8152_MAX_RX; i++) {
 		INIT_LIST_HEAD(&tp->rx_info[i].list);
 		ret = r8152_submit_rx(tp, &tp->rx_info[i], GFP_KERNEL);
-		if (ret)
+		if (ret) {
+			i++;
 			break;
+		}
+	}
+
+	INIT_LIST_HEAD(&rx_queue);
+	for (; i < RTL8152_MAX_RX; i++) {
+		struct rx_agg *agg = &tp->rx_info[i];
+		struct urb *urb = agg->urb;
+
+		INIT_LIST_HEAD(&agg->list);
+		urb->actual_length = 0;
+		list_add_tail(&agg->list, &rx_queue);
+	}
+
+	if (!list_empty(&rx_queue)) {
+		unsigned long flags;
+
+		spin_lock_irqsave(&tp->rx_lock, flags);
+		list_splice_tail(&rx_queue, &tp->rx_done);
+		spin_unlock_irqrestore(&tp->rx_lock, flags);
 	}
 
 	return ret;