===================================================================
@@ -440,36 +440,71 @@ lto_output_tree_1 (struct output_block *
}
}
-struct sccs
+class DFS
{
- unsigned int dfsnum;
- unsigned int low;
+public:
+ DFS (struct output_block *ob, tree expr, bool ref_p, bool this_ref_p,
+ bool single_p);
+ ~DFS ();
+
+ struct scc_entry
+ {
+ tree t;
+ hashval_t hash;
+ };
+ vec<scc_entry> sccstack;
+
+private:
+ struct sccs
+ {
+ unsigned int dfsnum;
+ unsigned int low;
+ };
+
+ static int scc_entry_compare (const void *, const void *);
+
+ void DFS_write_tree_body (struct output_block *ob,
+ tree expr, sccs *expr_state, bool ref_p,
+ bool single_p);
+
+ void DFS_write_tree (struct output_block *ob, sccs *from_state,
+ tree expr, bool ref_p, bool this_ref_p,
+ bool single_p);
+ hashval_t
+ hash_scc (struct output_block *ob, unsigned first, unsigned size);
+
+ unsigned int next_dfs_num;
+ struct pointer_map_t *sccstate;
+ struct obstack sccstate_obstack;
};
-struct scc_entry
+DFS::DFS (struct output_block *ob, tree expr, bool ref_p, bool this_ref_p,
+ bool single_p)
{
- tree t;
- hashval_t hash;
-};
+ sccstack.create (0);
+ sccstate = pointer_map_create ();
+ gcc_obstack_init (&sccstate_obstack);
+ next_dfs_num = 1;
+ DFS_write_tree (ob, NULL, expr, ref_p, this_ref_p, single_p);
+}
-static unsigned int next_dfs_num;
-static vec<scc_entry> sccstack;
-static struct pointer_map_t *sccstate;
-static struct obstack sccstate_obstack;
-
-static void
-DFS_write_tree (struct output_block *ob, sccs *from_state,
- tree expr, bool ref_p, bool this_ref_p);
+DFS::~DFS ()
+{
+ sccstack.release ();
+ pointer_map_destroy (sccstate);
+ obstack_free (&sccstate_obstack, NULL);
+}
/* Handle the tree EXPR in the DFS walk with SCC state EXPR_STATE and
DFS recurse for all tree edges originating from it. */
-static void
-DFS_write_tree_body (struct output_block *ob,
- tree expr, sccs *expr_state, bool ref_p)
+void
+DFS::DFS_write_tree_body (struct output_block *ob,
+ tree expr, sccs *expr_state, bool ref_p,
+ bool single_p)
{
#define DFS_follow_tree_edge(DEST) \
- DFS_write_tree (ob, expr_state, DEST, ref_p, ref_p)
+ DFS_write_tree (ob, expr_state, DEST, ref_p, ref_p, single_p)
enum tree_code code;
@@ -690,18 +725,26 @@ DFS_write_tree_body (struct output_block
#undef DFS_follow_tree_edge
}
-/* Return a hash value for the tree T. */
+/* Return a hash value for the tree T.
+ CACHE holds hash values of trees outside current SCC. MAP, if non-NULL,
+ may hold hash values if trees inside current SCC. */
static hashval_t
-hash_tree (struct streamer_tree_cache_d *cache, tree t)
+hash_tree (struct streamer_tree_cache_d *cache, hash_map<tree, hashval_t> *map, tree t)
{
inchash hstate;
#define visit(SIBLING) \
do { \
unsigned ix; \
- if (SIBLING && streamer_tree_cache_lookup (cache, SIBLING, &ix)) \
+ if (!SIBLING) \
+ hstate.add_int (0); \
+ else if (streamer_tree_cache_lookup (cache, SIBLING, &ix)) \
hstate.add_int (streamer_tree_cache_get_hash (cache, ix)); \
+ else if (map) \
+ hstate.add_int (*map->get (SIBLING)); \
+ else \
+ hstate.add_int (1); \
} while (0)
/* Hash TS_BASE. */
@@ -905,23 +948,7 @@ hash_tree (struct streamer_tree_cache_d
if (CODE_CONTAINS_STRUCT (code, TS_TYPED))
{
- if (POINTER_TYPE_P (t))
- {
- /* For pointers factor in the pointed-to type recursively as
- we cannot recurse through only pointers.
- ??? We can generalize this by keeping track of the
- in-SCC edges for each tree (or arbitrarily the first
- such edge) and hashing that in in a second stage
- (instead of the quadratic mixing of the SCC we do now). */
- hashval_t x;
- unsigned ix;
- if (streamer_tree_cache_lookup (cache, TREE_TYPE (t), &ix))
- x = streamer_tree_cache_get_hash (cache, ix);
- else
- x = hash_tree (cache, TREE_TYPE (t));
- hstate.merge_hash (x);
- }
- else if (code != IDENTIFIER_NODE)
+ if (code != IDENTIFIER_NODE)
visit (TREE_TYPE (t));
}
@@ -1116,8 +1143,8 @@ hash_tree (struct streamer_tree_cache_d
/* Compare two SCC entries by their hash value for qsorting them. */
-static int
-scc_entry_compare (const void *p1_, const void *p2_)
+int
+DFS::scc_entry_compare (const void *p1_, const void *p2_)
{
const scc_entry *p1 = (const scc_entry *) p1_;
const scc_entry *p2 = (const scc_entry *) p2_;
@@ -1131,40 +1158,159 @@ scc_entry_compare (const void *p1_, cons
/* Return a hash value for the SCC on the SCC stack from FIRST with
size SIZE. */
-static hashval_t
-hash_scc (struct streamer_tree_cache_d *cache, unsigned first, unsigned size)
+hashval_t
+DFS::hash_scc (struct output_block *ob,
+ unsigned first, unsigned size)
{
+ unsigned int last_classes = 0, iterations = 0;
+
/* Compute hash values for the SCC members. */
for (unsigned i = 0; i < size; ++i)
- sccstack[first+i].hash = hash_tree (cache, sccstack[first+i].t);
+ sccstack[first+i].hash = hash_tree (ob->writer_cache, NULL,
+ sccstack[first+i].t);
if (size == 1)
return sccstack[first].hash;
- /* Sort the SCC of type, hash pairs so that when we mix in
- all members of the SCC the hash value becomes independent on
- the order we visited the SCC. Produce hash of the whole SCC as
- combination of hashes of individual elements. Then combine that hash into
- hash of each element, so othewise identically looking elements from two
- different SCCs are distinguished. */
- qsort (&sccstack[first], size, sizeof (scc_entry), scc_entry_compare);
-
- hashval_t scc_hash = sccstack[first].hash;
- for (unsigned i = 1; i < size; ++i)
- scc_hash = iterative_hash_hashval_t (scc_hash,
- sccstack[first+i].hash);
- for (unsigned i = 0; i < size; ++i)
- sccstack[first+i].hash = iterative_hash_hashval_t (sccstack[first+i].hash, scc_hash);
- return scc_hash;
+ /* We aim to get unique hash for every tree within SCC and compute hash value
+ of the whole SCC by combing all values together in an stable (entry point
+ independent) order. This guarantees that the same SCC regions within
+ different translation units will get the same hash values and therefore
+ will be merged at WPA time.
+
+ Often the hashes are already unique. In that case we compute scc hash
+ by combining individual hash values in an increasing order.
+
+ If thre are duplicates we seek at least one tree with unique hash (and
+ pick one with minimal hash and this property). Then we obtain stable
+ order by DFS walk starting from this unique tree and then use index
+ within this order to make individual hash values unique.
+
+ If there is no tree with unique hash, we iteratively propagate the hash
+ values across the internal edges of SCC. This usually quickly leads
+ to unique hashes. Consider, for example, an SCC containing two pointers
+ that are identical except for type they point and assume that these
+ types are also part of the SCC.
+ The propagation will add the points-to type information into their hash
+ values. */
+ do
+ {
+ /* Sort the SCC so we can easily see check for uniqueness. */
+ qsort (&sccstack[first], size, sizeof (scc_entry), scc_entry_compare);
+
+ unsigned int classes = 1;
+ int firstunique = -1;
+
+ /* Find tree with lowest unique hash (if it exists) and compute
+ number of equivalence classes. */
+ if (sccstack[first].hash != sccstack[first+1].hash)
+ firstunique = 0;
+ for (unsigned i = 1; i < size; ++i)
+ if (sccstack[first+i-1].hash != sccstack[first+i].hash)
+ {
+ classes++;
+ if (firstunique == -1
+ && (i == size - 1
+ || sccstack[first+i+1].hash != sccstack[first+i].hash))
+ firstunique = i;
+ }
+
+ /* If we found tree with unique hash; stop the iteration. */
+ if (firstunique != -1
+ /* Also terminate if we run out of iterations or if the number of
+ equivalence classes is no longer increasing.
+ For example a cyclic list of trees that are all equivalent will
+ never have unique entry point; we however do not build such SCCs
+ in our IL. */
+ || classes <= last_classes || iterations > 16)
+ {
+ hashval_t scc_hash;
+
+ /* If some hashes are not unique (CLASSES != SIZE), use the DFS walk
+ starting from FIRSTUNIQUE to obstain stable order. */
+ if (classes != size && firstunique != -1)
+ {
+ hash_map <tree, hashval_t> map(size*2);
+
+ /* Store hash values into a map, so we can associate them with
+ reordered SCC. */
+ for (unsigned i = 0; i < size; ++i)
+ map.put (sccstack[first+i].t, sccstack[first+i].hash);
+
+ DFS again (ob, sccstack[first+firstunique].t, false, false, true);
+ gcc_assert (again.sccstack.length () == size);
+
+ memcpy (sccstack.address () + first,
+ again.sccstack.address (),
+ sizeof (scc_entry) * size);
+
+ /* Update hash values of individual members by hashing in the
+ index within the stable order. This ensures uniqueness.
+ Also compute the scc_hash by mixing in all hash values in the
+ stable order we obtained. */
+ sccstack[first].hash = *map.get (sccstack[first].t);
+ scc_hash = sccstack[first].hash;
+ for (unsigned i = 1; i < size; ++i)
+ {
+ sccstack[first+i].hash
+ = iterative_hash_hashval_t (i,
+ *map.get (sccstack[first+i].t));
+ scc_hash = iterative_hash_hashval_t (scc_hash,
+ sccstack[first+i].hash);
+ }
+ }
+ /* If we got unique hash values for each tree, then sort already
+ ensured entry point independent order. Only compute the final
+ scc hash.
+
+ If we failed to find the unique entry point, we go by the same
+ route. We will eventually introduce unwanted hash conflicts. */
+ else
+ {
+ scc_hash = sccstack[first].hash;
+ for (unsigned i = 1; i < size; ++i)
+ scc_hash = iterative_hash_hashval_t (scc_hash,
+ sccstack[first+i].hash);
+ /* We can not 100% guarantee that the hash will not conflict in
+ in a way so the unique hash is not found. This however
+ should be extremely rare situation. ICE for now so possible
+ issues are found and evaulated. */
+ gcc_checking_assert (classes == size);
+ }
+
+ /* To avoid conflicts across SCCs iteratively hash the whole SCC
+ hash into the hash of each of the elements. */
+ for (unsigned i = 0; i < size; ++i)
+ sccstack[first+i].hash
+ = iterative_hash_hashval_t (sccstack[first+i].hash, scc_hash);
+ return scc_hash;
+ }
+
+ last_classes = classes;
+ iterations++;
+
+ /* We failed to identify the entry point; propagate hash values across
+ the edges. */
+ {
+ hash_map <tree, hashval_t> map(size*2);
+ for (unsigned i = 0; i < size; ++i)
+ map.put (sccstack[first+i].t, sccstack[first+i].hash);
+
+ for (unsigned i = 0; i < size; i++)
+ sccstack[first+i].hash = hash_tree (ob->writer_cache, &map,
+ sccstack[first+i].t);
+ }
+ }
+ while (true);
}
/* DFS walk EXPR and stream SCCs of tree bodies if they are not
already in the streamer cache. Main routine called for
each visit of EXPR. */
-static void
-DFS_write_tree (struct output_block *ob, sccs *from_state,
- tree expr, bool ref_p, bool this_ref_p)
+void
+DFS::DFS_write_tree (struct output_block *ob, sccs *from_state,
+ tree expr, bool ref_p, bool this_ref_p, bool single_p)
{
unsigned ix;
sccs **slot;
@@ -1196,10 +1342,10 @@ DFS_write_tree (struct output_block *ob,
;
else if (TREE_CODE (expr) == INTEGER_CST
&& !TREE_OVERFLOW (expr))
- DFS_write_tree (ob, cstate, TREE_TYPE (expr), ref_p, ref_p);
+ DFS_write_tree (ob, cstate, TREE_TYPE (expr), ref_p, ref_p, single_p);
else
{
- DFS_write_tree_body (ob, expr, cstate, ref_p);
+ DFS_write_tree_body (ob, expr, cstate, ref_p, single_p);
/* Walk any LTO-specific edges. */
if (DECL_P (expr)
@@ -1209,7 +1355,7 @@ DFS_write_tree (struct output_block *ob,
/* Handle DECL_INITIAL for symbols. */
tree initial = get_symbol_initial_value (ob->decl_state->symtab_node_encoder,
expr);
- DFS_write_tree (ob, cstate, initial, ref_p, ref_p);
+ DFS_write_tree (ob, cstate, initial, ref_p, ref_p, single_p);
}
}
@@ -1219,6 +1365,11 @@ DFS_write_tree (struct output_block *ob,
unsigned first, size;
tree x;
+ /* If we are re-walking a single leaf-SCC just return and
+ let the caller access the sccstack. */
+ if (single_p)
+ return;
+
/* Pop the SCC and compute its size. */
first = sccstack.length ();
do
@@ -1234,7 +1385,7 @@ DFS_write_tree (struct output_block *ob,
unsigned scc_entry_len = 0;
if (!flag_wpa)
{
- scc_hash = hash_scc (ob->writer_cache, first, size);
+ scc_hash = hash_scc (ob, first, size);
/* Put the entries with the least number of collisions first. */
unsigned entry_start = 0;
@@ -1258,6 +1409,18 @@ DFS_write_tree (struct output_block *ob,
sccstack[first + i] = sccstack[first + entry_start + i];
sccstack[first + entry_start + i] = tem;
}
+
+ if (scc_entry_len == 1)
+ ; /* We already sorted SCC deterministically in hash_scc. */
+ else
+ /* Check that we have only one SCC.
+ Naturally we may have conflicts if hash function is not
+ strong enough. Lets see how far this gets. */
+ {
+#ifdef ENABLE_CHECKING
+ gcc_unreachable ();
+#endif
+ }
}
/* Write LTO_tree_scc. */
@@ -1377,13 +1540,7 @@ lto_output_tree (struct output_block *ob
/* Save ob state ... */
/* let's see ... */
in_dfs_walk = true;
- sccstate = pointer_map_create ();
- gcc_obstack_init (&sccstate_obstack);
- next_dfs_num = 1;
- DFS_write_tree (ob, NULL, expr, ref_p, this_ref_p);
- sccstack.release ();
- pointer_map_destroy (sccstate);
- obstack_free (&sccstate_obstack, NULL);
+ DFS (ob, expr, ref_p, this_ref_p, false);
in_dfs_walk = false;
/* Finally append a reference to the tree we were writing.