===================================================================
@@ -10048,11 +10048,12 @@
--------------------------------
function Prefix_Is_Formal_Parameter (N : Node_Id) return Boolean is
- Sel_Comp : Node_Id := N;
+ Sel_Comp : Node_Id;
begin
-- Move to the left-most prefix by climbing up the tree
+ Sel_Comp := N;
while Present (Parent (Sel_Comp))
and then Nkind (Parent (Sel_Comp)) = N_Selected_Component
loop
@@ -10065,20 +10066,12 @@
-- Start of processing for Has_Inferable_Discriminants
begin
- -- For identifiers and indexed components, it is sufficient to have a
- -- constrained Unchecked_Union nominal subtype.
-
- if Nkind_In (N, N_Identifier, N_Indexed_Component) then
- return Is_Unchecked_Union (Base_Type (Etype (N)))
- and then
- Is_Constrained (Etype (N));
-
-- For selected components, the subtype of the selector must be a
-- constrained Unchecked_Union. If the component is subject to a
-- per-object constraint, then the enclosing object must have inferable
-- discriminants.
- elsif Nkind (N) = N_Selected_Component then
+ if Nkind (N) = N_Selected_Component then
if Has_Per_Object_Constraint (Entity (Selector_Name (N))) then
-- A small hack. If we have a per-object constrained selected
@@ -10087,19 +10080,20 @@
if Prefix_Is_Formal_Parameter (N) then
return True;
- end if;
-- Otherwise, check the enclosing object and the selector
- return Has_Inferable_Discriminants (Prefix (N))
- and then
- Has_Inferable_Discriminants (Selector_Name (N));
- end if;
+ else
+ return Has_Inferable_Discriminants (Prefix (N))
+ and then Has_Inferable_Discriminants (Selector_Name (N));
+ end if;
-- The call to Has_Inferable_Discriminants will determine whether
-- the selector has a constrained Unchecked_Union nominal type.
- return Has_Inferable_Discriminants (Selector_Name (N));
+ else
+ return Has_Inferable_Discriminants (Selector_Name (N));
+ end if;
-- A qualified expression has inferable discriminants if its subtype
-- mark is a constrained Unchecked_Union subtype.
@@ -10107,9 +10101,14 @@
elsif Nkind (N) = N_Qualified_Expression then
return Is_Unchecked_Union (Etype (Subtype_Mark (N)))
and then Is_Constrained (Etype (Subtype_Mark (N)));
- end if;
- return False;
+ -- For all other names, it is sufficient to have a constrained
+ -- Unchecked_Union nominal subtype.
+
+ else
+ return Is_Unchecked_Union (Base_Type (Etype (N)))
+ and then Is_Constrained (Etype (N));
+ end if;
end Has_Inferable_Discriminants;
-------------------------------