@@ -211,6 +211,7 @@
* @param __r A %shared_ptr.
* @post get() == __r.get() && use_count() == __r.use_count()
*/
+ shared_ptr(const shared_ptr&) = default; // never throws
template<typename _Tp1, typename = typename
std::enable_if<std::is_convertible<_Tp1*, _Tp*>::value>::type>
shared_ptr(const shared_ptr<_Tp1>& __r)
@@ -264,6 +265,7 @@
constexpr shared_ptr(nullptr_t __p)
: __shared_ptr<_Tp>(__p) { }
+ shared_ptr& operator=(const shared_ptr&) = default;
template<typename _Tp1>
shared_ptr&
operator=(const shared_ptr<_Tp1>& __r) // never throws
Fixing a typo when Cc'ing Matthias Klose. --- When compiling with a compiler that is conformant to the c++11 spec for PR c++/50500, std::shared_ptr must have an explicitly defined copy constructor. Backported from revision 180159. The rest of the revision includes new functionality, so only this part should be applied to 4.6. This has been tested on an x86_64 host with clang 3.0 as the C++ compiler. PR c++/50500 * Explicitly define default copy constructor for std::shared_ptr 15:15:03 171293 +++ b/src/libstdc++-v3/include/bits/shared_ptr_base.h 2011/05/18 22:59:17 173882 @@ -799,7 +801,9 @@ : _M_ptr(__p), _M_refcount(__r._M_refcount) // never throws { } - // generated copy constructor, assignment, destructor are fine. + __shared_ptr(const __shared_ptr&) = default; // never throws + __shared_ptr& operator=(const __shared_ptr&) = default; // never throws + ~__shared_ptr() = default; template<typename _Tp1, typename = typename std::enable_if<std::is_convertible<_Tp1*, _Tp*>::value>::type> @@ -1216,7 +1220,9 @@ : _M_ptr(0), _M_refcount() // never throws { } - // Generated copy constructor, assignment, destructor are fine. + __weak_ptr(const __weak_ptr&) = default; // never throws + __weak_ptr& operator=(const __weak_ptr&) = default; // never throws + ~__weak_ptr() = default; // The "obvious" converting constructor implementation: //